Find the general solution of the equation `4cos^2x=1`

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#### Solution

Given:

`4cos^2x=1`

`cos^2x=1/4`

`cos^2x=cos^2(pi/3)`

`["Using " cos^2x=cos^2alpha => x=npi+-alpha]`

`x=npi+-pi/3" where " n in Z`

Concept: Trigonometric Functions - General Solution of Trigonometric Equation of the Type

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